tag:blogger.com,1999:blog-2514352312859447561.post8014604539471687353..comments2024-08-03T01:47:46.286-04:00Comments on Bad Data, Bad!: Wednesday Brain Teaser 2-20-13bs kinghttp://www.blogger.com/profile/02871717971078952304noreply@blogger.comBlogger5125tag:blogger.com,1999:blog-2514352312859447561.post-38100445164495840522013-02-22T07:49:01.911-05:002013-02-22T07:49:01.911-05:00SJ definitely got the answer I was looking for, bu...SJ definitely got the answer I was looking for, but James answer was quite lovely. Not sure how I missed that one, but I'm glad to be corrected!bs kinghttps://www.blogger.com/profile/02871717971078952304noreply@blogger.comtag:blogger.com,1999:blog-2514352312859447561.post-9808372080009319832013-02-21T17:59:29.921-05:002013-02-21T17:59:29.921-05:00No googling when it's squares and cubes. Thos...No googling when it's squares and cubes. Those and primes are the center of my numbers OCD. I used to factor things like the odometer for fun.<br /><br />I had SJ's answer, but James's is much more elegant. I hazarded 512 as a guess because it was barely over 500, and I thought that might be the trick. But it didn't work, of course, because it's 2^9, and thus not a square. But figuring that cued me immediately that 9^3 was going to switch that and had to work.<br /><br />But of course, 9 actually does begin with 9.Assistant Village Idiothttps://www.blogger.com/profile/01978011985085795099noreply@blogger.comtag:blogger.com,1999:blog-2514352312859447561.post-60777761244954268352013-02-21T17:42:36.894-05:002013-02-21T17:42:36.894-05:00I didn't google. I wrote a quick pari+bash sc...I didn't google. I wrote a quick pari+bash script to look for all the possibilities.jameshttps://www.blogger.com/profile/01792036361407527304noreply@blogger.comtag:blogger.com,1999:blog-2514352312859447561.post-78452029947286075682013-02-21T16:04:56.879-05:002013-02-21T16:04:56.879-05:003^2=9<500, satisfying conditions 2 and 3.3^2=9<500, satisfying conditions 2 and 3.jameshttps://www.blogger.com/profile/01792036361407527304noreply@blogger.comtag:blogger.com,1999:blog-2514352312859447561.post-35727425868008907332013-02-21T09:20:22.120-05:002013-02-21T09:20:22.120-05:00729 = 9^3 = 27^2
I got this by looking at cubes o...729 = 9^3 = 27^2<br /><br />I got this by looking at cubes of numbers between 1 and 10. This was the second one that could be re-written as a square of some other number.<br /><br />The first is 64 = 4^3 = 8^2, which would fit all 3 constraints. But doesn't fit the problem restatement...<br /><br />No Googling. SJhttps://www.blogger.com/profile/12043843405366080460noreply@blogger.com